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Aptitude - Aptitude-Average And Interests

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David invested certain amount in three different schemes A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme C was 150% of the amount invested in Scheme A and 240% of the amount invested in Scheme B, what was the amount invested in Scheme B?

  • a
  • b
  • c
  • d
  • OOPS, your answer is incorrect

    Let x , y and x be his investments in A, B and C respectively. Then Interest on x at 10% for 1 year + Interest on y at 12% for 1 year + Interest on z at 15% for 1 year = 3200 [(x×10×1)/100] +[(y×12×1)/100]+[(z×15×1)/100]=3200 ⇒10x+12y+15z=320000−−−(1) Amount invested in Scheme C was 240% of the amount invested in Scheme B =>z=240y/100=60y/25=12y/5−−−(2) Amount invested in Scheme C was 150% of the amount invested in Scheme A =>z=150x/100=3x/2=>x=2z/3=(2/3)×(12y/5) = 8y/5−−(3) From(1),(2) and (3), 10x + 12y + 15z = 320000 10(8y/5)+12/y+15(12/y5)=320000 16y+12y+36y=320000 64y=320000 y=320000/64=10000/2=5000 i.e.,Amount invested in Scheme B = Rs.5000

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