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From a 20lt solution of salt and water with 20% salt, 2lt of water is evaporated. Find the new % concentration of salt?
OOPS, your answer is incorrect
In 20lt, salt = 20% => 4 lt. New volume = 18 lt (2 lt evaporated) So, new % = 4/18 X 100 = 22.22%
A reduction of 10% in price of sugar enables a housewife to buy 5 kg more for Rs. 300/-. Find the reduced price per kg of sugar?
OOPS, your answer is incorrect
Total money = Rs. 300. Saving of the lady = 10% of 300 = 30/- With 30/- she bought 5 kg sugar => each kg costs Rs. 6/-
In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and 15% had both type of lunch. If 96 people were present, how many did not eat either type of lunch ?
OOPS, your answer is incorrect
n(A)=(60100∗96)=2885n(B)=(30100∗96)=1445n(A∩B)=(15100∗96)=725People who have either or both lunchn(A∪B)=2885+1445−725=3605=72
So People who do no have either lunch were = 96 -72
= 24
Out of 450 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ?
OOPS, your answer is incorrect
Students who play cricket, n(A) = 325
Students who play football, n(B) = 175
Total students who play either or both games,
=n(A∪B)=450−50=400Required Number,n(A∩B)=n(A)+n(B)−n(A∪B)=325+175−400=100
In an examination, 34% of the students failed in mathematics and 42% failed in English. If 20% of the students failed in both the subjects, then find the percentage of students who passed in both the subjects.
OOPS, your answer is incorrect
Failed in mathematics, n(A) = 34
Failed in English, n(B) = 42
n(A∪B)=n(A)+n(B)−n(A∩B)=34+42−20=56Failed in either or both subjects are 56Percentage passed = (100−56)%=44%