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A travels from B to C a distance of 250 miles in 5.5 hours. He returns to B in 4 hours 40 minutes. His average speed is ?
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Total distance = 250 + 250 = 500 miles
Total time = 5 hr 30 min + 4 hr 40 min = 10 hr 10 min = 10 (1/6)
Speed = distance / time
Speed = 500 / 10(1/6) = 3000 / 61
Average speed = 49.18 ≈ 50
Walking at the rate of 4 kmph a man cover certain distance in 2hr 45 min. Running at a speed of 16.5 kmph the man will cover the same distance in ?
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From the problem we understand that the distance is same in both scenarios. Only speed and time vary.
While walking, distance1 = speed1 x time1
While running, distance2 = speed2 x time2
distance1 = distance2
speed1 x time1 = speed2 x time2
4 x 2 hr 45 min = 16.5 x time2
4 x 165 = 16.5 x time2 (Changing time in minutes)
time2 = 40 min.
In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:
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A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is ?
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