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2 trains starting at the same time from 2 stations 200 km apart and going in opposite direction cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds?
OOPS, your answer is incorrect
If the trains cross each other at a distance of 110 km from one of the stations, at same time, they cover 110 km & 90 km respectively
so ratio of their speed =110: 90 = 11: 9
Excluding stopages, the speed of a bus is 54 kmph and including stopages, it is 45 kmph. For how many minutes does the bus stop per hour?
OOPS, your answer is incorrect
Due to stoppages, it covers 9 km less.\n\nTime taken to cover 9 km = (9/54 x 60) min = 10 min.
Two boys starting from the same place walk at a rate of 5 kmph and 5.5 kmph respectively. What time will they take to be 8.5 km apart, if they walk in the same direction?
OOPS, your answer is incorrect
The relative speed of the boys = 5.5 kmph – 5 kmph = 0.5 kmph
Distance between them is 8.5 km
Required time = 8.5km / 0.5 kmph = 17 hrs
If train runs at a speed of 48 kmph on an average, a train covers a distance in 50 min, the train must run to reduce the time of journey to 40 min will be, at which speed?
OOPS, your answer is incorrect
Present Time = 50 mins
Converting into hour format --> 50/60 hr = 5/6 hr
Present Speed = 48 kmph
Therefore, distance = S*T = 48 * (5/6) = 40 km
To run in 40 min, time = 40/60 hr = 2/3 hr
Required speed = Distance/ time = 40 * (3/2) kmph = 60 kmph
A snail is at the bottom of a 20 meters deep pit. Every day the snail climbs 5 meters upwards, but at night it slides 4 meters back downwards. How many days does it take before the snail reaches the top of the pit?
OOPS, your answer is incorrect
Since the snail moves up 1 meter a day (5 meters upwards, but at night it slides 4 meters back downwards) so it will reach 15 meters in 15 days.
Next day it will again climb 5 meters upward and reaches the top. (During daytime itself)