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A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
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A 100 meter long train is running at the speed of 30 km/hr. Find the time taken by it to pass a man standing near the railway line ?
OOPS, your answer is incorrect
Since the options are given in sec. we have to convert the speed of the train in terms of m/s.
Speed of the train = 30 km/hr = 30 x (5/18) = 25/3 (m/s)
So, the train passes 25 meters in 3 seconds (From the above equation).
Therefore, the train will pass 100 meters in 4 x 3 = 12 sec
A train moves with a speed of 108 kmph. Its speed in metres per second is
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1 kmph = 1000 m / (60 x 60) s = 1000/3600 (m/s) = 5/18 (m/s)
So, 108 kmph = 108 x (5/18) = 30 (m/s)
If a man runs at 3 m/s. How many km does he run in 1hr 40min
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Speed of the man = 3 m/s
After convering to kmph --> 3*(18/5) kmph = 54/5 kmph
1hr 40min --> 1 (2/3) hr --> 5/3 hr
Distance covered in 5/3 hrs = (54/5) * (5/3) = 18 km
In covering a distance of 30 km, Sachin takes 2 hours more than Rohit. If Sachin doubles his speed, then he would take 1 hour less than Rohit. Sachin speed is:
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Let Sachin’s speed be x km/hr.
Then, 30/x - 30/2x = 3
30/x --> Actual speed
30/2x --> After doubling the speed
3 --> he saves 3 hours (the 2 late hours + 1 advance hour)
Solving the equation,
6x = 30
x = 5 km/hr.