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12 children take 16 days to complete a work which can be completed by 8 adults in 12 days. 16 adults started working and after 3 days 10 adults left and 4 children joined them. How many days will it take them to complete the remaining work?
OOPS, your answer is incorrect
Let 1 child’s 1 day’s work = x and 1 adults 1 days work = y.
Then, 12x = 1/16 or x = 1/192 and 8y= 1/12 or Y = 1/196. Work done in 3 days = (16 * (1/96)*3)= 1/2
Wrk left = (1 - (1/2)) = 1/2
(6 adults + 4 children)s 1 days work = (6/96) + (4/192) = 1/12
1/12 work is done by them in 1 day.
1/2 work is done by them in (12 * (1/2)) = 6 days.
A and B together can complete a piece of work in 35 days while A alone can complete the same work in 60 days. B alone will be able to complete the same work in ?
OOPS, your answer is incorrect
(A+B)s 1 days work = 1/35 and As 1 days work = 1/60
Bs 1 days work =(1/35 - 1/60) = 5/420 = 1/84
A can do a piece of work in 15 days and B alone can do it in 10 days. B works at it for 5 days and then leaves. A alone can finish the remaining work in ?
OOPS, your answer is incorrect
Bs 5 days work = ((1/10) * 5) = 1/2
Remaining work = (1-(1/2)) = 1/2
A can do 1/2 work in 7and half days.
Twelve men can complete a work in 8 days. Three days after they started the work, 3 more men joined. In how many days will all of them together complete the remaining work?
OOPS, your answer is incorrect
1 mans 1 days = 1/96
12 menS 3 days work = (1/8) * 3 = 3/8.
Remaining work 1 — (3/8) = 5/8 15 mens 1 days work = 15/96
Now, 15/96 work is done by them in 1 day
5/8 work is done by them in (96/15) * (5/8) = 4 days.