 # Aptitude - Aptitude-Time And Works

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A does a work in 10 days and B does the same work in 15 days. In how many days they together will do the same work?

• • • • a
• b
• c
• d

A\'s 1 day\'s work    = 1/10
and B\'s 1 day\'s work    = 1/15.
(A+B)\'s 1 day\'s work     = (1/10+1/15)
= 1/6.

10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?

• • • • a
• b
• c
• d

1 woman\'s 1 day\'s work    = 1/70
1 child\'s 1 day\'s work    = 1/140.
(5 women +10 children)\'s 1 day\'s work    = (5/70+10/140)
= (1/14+1/14)
= 1/7.

A tyre has punctures. The first puncture alone would have made the tyre flat in 9 minutes and the second alone would have done it in 6 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat?

• • • • a
• b
• c
• d

1 minute\'s work of both the punctures    = (1/9+1/6)
= 5/18
So, both the punctures will make the tyre flat in     = 18/5
= 3x3/5 days.

A man can do a job in 15 days. His father takes 20 days and his son finishes it in 25 days. How long will they take to complete the job if they all work together?

• • • • a
• b
• c
• d

1 day\'s work of the three persons    = (1/15+1/20+1/25)
47/300.
So, all the three together will complete the work in     = 300/47
= 6.4 days.

5 men and 2 boys working together can do four times as much work as a man and a boy. Working capacities of a woman and a boy are in the ratio?

• • • • a
• b
• c
• d