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If 10 men or 18 boys can do a piece of work in 15 days, then 25 men and 15 boys together will do twice the work in ?
OOPS, your answer is incorrect
10 men = 18boy hence 1 man = 18/10 boys
25 men + 15 boys = (25 * 18/10) + 15 = 60
now more work more days
more boys less days1 * 60 * x = 2*18*15 or x = (2*18*15)/60 = 9 days
A certain number of men complete a piece of work in 60 days. If there were 8 men more, the work could be finished in 10 days less. How many men were originally there ?
OOPS, your answer is incorrect
Originally 1et there be x men.
More men, Less days
(x + 8) : x ∷ 60:50
So, x + 8 / x = 60/50 or x = 40.
A, B and C can do apiece of work in 11 days, 20 days and 55 days respectively, working alone. How soon can the work be done if A is assisted by B and C on alternate days?
OOPS, your answer is incorrect
(A+B)s 1 days Work = (1/11) + (1/20) = 31/220
(A+C)S 1 days work = (1/11) + (1/55) = 6/55
Work done in 2 days = (31/220) + (6/55) = 55/220 = 1/4
Now, 1/4 work is done in 2 days.
Whole work will be done in (4 x 2) = 8 days.
In time and work, six days after men started working,12 men can complete a work in 18 days after that 4 men joined them. How many days will all of them take to finish the remaining work?
OOPS, your answer is incorrect
(12 * 18) men can complete the work in 1 day.
1 mans 1 days work = 1/216
12 men’s 6 days work = (1/18)*6 = 1/3
remaining work = 1 - (1/3) = 2/3
16 mens 1 days work = 16/216 = 2/27
2/27 work is done by them in 1 day.
2/3 work is done by them in (27/2)*(2/3) = 9 days.
A is twice as good a workman as B and ‘together they complete a work in 15 days. In how many days can the work be completed by B alone?
OOPS, your answer is incorrect
(As 1 days work):(Bs 1 days work) = 2: 1.
(A+B)s 1 day’s work= 1/15.
Divide 1/15 in the ratio 2 : 1
Bs 1 days work = (1/15) * (1/3) = 1/45
B alone can finish the work in 45 days.